The oxidation number of the underlined atom i | vedclass

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Question

(B) $(1)$ $HAuCl_4 \Rightarrow (+1) + x + 4(-1) = 0 \Rightarrow x = +3$ $(2)$ $Cu_2\underline{O} \Rightarrow 2(+1) + x = 0 \Rightarrow x = -2$ $(3)$ $

Vedclass · Accepted Answer

$Cu_2\underline{O}$ is $-1$

Vedclass · Answer

(B) $(1)$ $HAuCl_4 \Rightarrow (+1) + x + 4(-1) = 0 \Rightarrow x = +3$ $(2)$ $Cu_2\underline{O} \Rightarrow 2(+1) + x = 0 \Rightarrow x = -2$ $(3)$ $\underline{Cl}O_3^{-} \Rightarrow x + 3(-2) = -1 \Rightarrow x = +5$ $(4)$ $K_2\underline{Cr}_2O_7 \Rightarrow 2(+1) + 2x + 7(-2) = 0 \Rightarrow 2x = +12 \Rightarrow x = +6$ The oxidation number of oxygen in $Cu_2O$ is $-2$, not $-1$. Therefore, option $B$ is incorrect.

The oxidation number of the underlined atom in the following species is given. Identify the incorrect option.

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